6p^2+15p+9=0

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Solution for 6p^2+15p+9=0 equation: 



6p^2+15p+9=0

a = 6; b = 15; c = +9;
Δ = b2-4ac
Δ = 152-4·6·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*6}=\frac{-18}{12}
=-1+1/2
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*6}=\frac{-12}{12}
=-1
$

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